(Take $V =0$ at infinity $)$
$V _{ C }=\frac{ K (\Sigma q )}{ R }$
$V _{ C }=\frac{ K (0)}{ R }=0$
Electric field at centre $\overrightarrow{ E }_{ B }=\Sigma \overrightarrow{ E }$
Let $E$ be electric field produced by each charge at the centre, then resultant electric field will be
$E _{ C }=0,$ since equal electric field vectors are acting at equal angle so their resultant is equal to zero.



