Ten charges are placed on the circumference of a circle of radius $R$ with constant angular separation between successive charges. Alternate charges $1,3,5,7,9$ have charge $(+q)$ each, while $2,4,6,8,10$ have charge $(-q)$ each. The potential $V$ and the electric field $E$ at the centre of the circle are respectively

(Take $V =0$ at infinity $)$

JEE MAIN 2020, Diffcult
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Sol. Potential of centre $= V =\quad \Sigma\left(\frac{ kq }{ R }\right)$

$V _{ C }=\frac{ K (\Sigma q )}{ R }$

$V _{ C }=\frac{ K (0)}{ R }=0$

Electric field at centre $\overrightarrow{ E }_{ B }=\Sigma \overrightarrow{ E }$

Let $E$ be electric field produced by each charge at the centre, then resultant electric field will be

$E _{ C }=0,$ since equal electric field vectors are acting at equal angle so their resultant is equal to zero.

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