MCQ
$\text{H}-\text{O}-\text{H}$ bond angle in water is :
- ✓$104.5^\circ$
- B$109.5^\circ$
- C$105.5^\circ$
- D$108.5^\circ$
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$C{H_3}C \equiv \,CC{H_3}\,\xrightarrow[{{\text{heat}}}]{{NaN{H_2}/{\text{inert solvent}}}}P$
$2N{O_2}\left( g \right) \rightleftharpoons {N_2}{O_4}\left( g \right)$ is
$\left( {R = \frac{{25}}{3}J/K.mol,\ln 2 = 0.7,\ln 3 = 1.1} \right)$
