MCQ
The acceleration of $10\, kg$ block when $F = 30\,N$ ........ $m/s^2$


- ✓$2$
- B$3$
- C$1$
- DNone

$\mathrm{F}-10=10 \mathrm{a}$
or $30-10=10 \mathrm{a}$
$\therefore a=\frac{20}{10}=2 \mathrm{m} / \mathrm{s}^{2}$
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A block is projected from the Point $A$ of inclined plane $A B$ along its surface with a velocity just sufficient to carry it to the top Point $B$ at a height $10 m$. After reaching the Point $B$ the block slides down on inclined plane $BC$. Time it takes to reach to the point $C$ from point $A$ is $t (\sqrt{2}+1) s$. The value of $t$ is........(use $g =10 m / s ^{2}$ )
| $Column-I$ | $Column-II$ |
| $(A)$ Angle of projection | $(p)$ $20\,m$ |
| $(B)$ Angle of velocity with horizontal after $4\,s$ | $(q)$ $80\,m$ |
| $(C)$ Maximum height | $(r)$ $45^{\circ}$ |
| $(D)$ Horizontal range | $(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$ |
$\lambda_\text{a}>\lambda_\text{f}$
$\lambda_\text{a}=\lambda_\text{f}$
$\lambda_\text{a}<\lambda_\text{f}$