The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1\, m$ suspended from the top of a roof at one end and with a load $W$ connected to the other end. If the cross-sectional area of the wire is $10^{-6}\, m^2$, calculate the Young’s modulus of the material of the wire.
AIIMS 2008, Medium
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$Y = \frac{F}{A}/\frac{{\Delta l}}{l} = \frac{{20 \times 1}}{{{{10}^{ - 6}} \times {{10}^{ - 4}}}}$
$ = 2 \times {10^{11}}N/{m^2}$
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