MCQ
The alkene that will give the same product with $HBr$ in the absence as well as in the presence of peroxide is
- ✓$2-$ butene
- B$1-$ butene
- Cpropene
- D$1-$ hexene
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Reason : The carbon atom carrying negative charge has an octet of electrons.
$(A)$ $\sigma$ orbital has a total of two nodal planes.
$(B)$ $\sigma^*$ orbital has one node in the $x z$-plane containing the molecular axis.
$(C)$ $\pi$ orbital has one node in the plane which is perpendicular to the molecular axis and goes through the center of the molecule.
$(D)$ $\pi^*$ orbital has one node in the $x y$-plane containing the molecular axis.
$Na _2 O + H _2 O \rightarrow 2 X$
$Cl _2 O _7+ H _2 O \rightarrow 2 Y$
$[K_b\,(CH_3COO^-) =10^{-9},pK_a\,(HPh)=9.6,log\,2 =0.3]$