MCQ
The amount of $BaSO_4$ formed upon mixing $100\,mL$ of $20.8\%$ $BaCl_2$ solution with $50\,mL$ of $9.8\%$ $H_2SO_4$ solution will be ............. $\mathrm{g}$

( $Ba = 137,\,\,Cl = 35.5,\,\,S = 32,\,\,H = 1$ and $O = 16$ )

  • $11.65$
  • B
    $23.3$
  • C
    $30.6$
  • D
    $33.2$

Answer

Correct option: A.
$11.65$
a
$\mathop {\mathop {BaC{l_2}}\limits_{208\,g} }\limits_{20.8\,g}  + \mathop {\mathop {{H_2}S{O_4}}\limits_{98\,g} }\limits_{9.8\,g}  \to \mathop {\mathop {BaS{O_4}}\limits_{233\,g} }\limits_{23.3\,g}  + \mathop {\mathop {2HCl}\limits_{73\,g} }\limits_{7.3\,g} $

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