The amplification factor of a triode is 20 and trans-conductance is 3 milli mho and load resistance 3 times 10^4 Omega, then the voltage gain

Q: The amplification factor of a triode is $20$ and trans-conductance is $3$ milli mho and load resistance $3 \times 10^4\ \Omega$, then the voltage gain is

$ \text { Using voltage gain } A_v=\frac{\mu}{1+\frac{r_p}{R_L}} \text { also } \mu=r_p \times g_m $ $ \Rightarrow r_p=\frac{\mu}{g_m}=\frac{20}{3 \times 10^{-3}} $ $ \therefore A_v=\frac{20}{1+\frac{20}{3 \times 10^{-3} \times 3 \times10^4}}=\frac{180}{11}=16.36 .$

MCQ

CBSE - English Medium

The amplification factor of a triode is $20$ and trans-conductance is $3$ milli mho and load resistance $3 \times 10^4\ \Omega$, then the voltage gain is

A$16.36$
B$28$
C$78$
D$108$

[RPMT 1996]

STD 12 Science
JEE physics
Electronics
NCERT

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