$A=\frac{V_{0}}{\omega_{0}}$
So equation of motion becomes $\frac{V_{0}}{\omega_{0}}=A \sin \omega_{0} t$ as there was no initial phase in the $SHM.$
There was no initial phase in the $SHM.$
Hence $B$ is correct.


$x = 0.01\cos \left( {\pi \,t + \frac{\pi }{4}} \right)$
The frequency of the motion will be
