The angular frequency of a spring block system is $\omega _0.$ This system is suspended from the ceiling of an elevator moving downwards with a constant speed $v_0.$ The block is at rest relative to the elevator. Lift is suddenly stopped. Assuming the downwards as a positive direction, choose the wrong statement :
  • AThe amplitude of the block is $\frac{v_0}{\omega _0}$
  • BThe initial phase of the block is $\pi .$
  • CThe equation of motion for the block is $\frac{v_0}{\omega _0} \sin \omega _0\,t.$
  • DThe maximum speed of the block is $v_0.$
Diffcult
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    Time period of a simple pendulum will be double, if we
    View Solution
  • 2
    A point object is kept in front of a plane mirror. The plane mirror is doing $SHM$ of amplitude $2\,cm$. The plane mirror moves along the $x-$ axis and $x-$ axis is normal to the mirror. The amplitude of the mirror is such that the object is always infront of the mirror. The amplitude of $SHM$ of the image is .... $cm$
    View Solution
  • 3
    A particle of mass $m$ is moving along a trajectory given by
    $x = x_0 + a\, cos\,\omega_1 t$
    $y = y_0 + b\, sin\,\omega_2t$
    The torque, acing on the particle about the origin, at $t = 0$ is
    View Solution
  • 4
    The potential energy of a particle of mass $0.1\,kg,$ moving along $x-$ axis, is given by $U = 5x(x-4)\,J$ where $x$ is in metres. It can be concluded that
    View Solution
  • 5
    A vibratory motion is represented by $x = 2A\,\cos \omega t + A\,\cos \,\left( {\omega t + \frac{\pi }{2}} \right) + A\,\cos \,\left( {\omega t + \pi } \right)$ $ + \frac{A}{2}\,\cos \left( {\omega t + \frac{{3\pi }}{2}} \right)$. The resultant amplitude of the motion is
    View Solution
  • 6
    The ratio of frequencies of two pendulums are $2 : 3$, then their length are in ratio
    View Solution
  • 7
    The amplitude of a simple pendulum, oscillating in air with a small spherical bob, decreases from $10\, cm$ to $8\, cm$ in $40\, seconds$ . Assuming that Stokes law is valid, and ratio of the coefficient of viscosity of air to that of carbon dioxide is $1.3$ . The time in which amplitude of this pendulum will reduce from $10\, cm$ to $5\, cm$ in carbon dioxide will be close to ..... $s$ $(ln\, 5 = 1.601,ln\, 2 = 0 .693)$
    View Solution
  • 8
    A pendulum is executing simple harmonic motion and its maximum kinetic energy is $K_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is $K_2$ then
    View Solution
  • 9
    The periodic time of a simple pendulum of length $1\, m $ and amplitude $2 \,cm $ is $5\, seconds$. If the amplitude is made $4\, cm$, its periodic time in seconds will be
    View Solution
  • 10
    Two massless springs with spring constants $2\,k$ and $2\,k$, carry $50\, g$ and $100 \,g$ masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be
    View Solution