MCQ
The atomic number of silicon is $14$. Its ground state electron configuration is
  • A
    $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1} 3 p^{3}$
  • B
    $1 s^{2} 2 s^{2} 2 p^{2} 2 p^{8} 3 s^{2}$
  • $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}$
  • D
    $1 s^{2} 2 s^{2} 2 p^{2} 2 s^{4}$

Answer

Correct option: C.
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}$
c
We know that s orbital contains maximum $2$ electrons and p contains maximum $6$ electrons. $s-$ orbitals filled by electron first then $p-$orbitals. According to this, option A should be right.

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