MCQ
The average thermal energy for a mono$-$atomic gas is : $\left( k _{ B }\right.$ is Boltzmann constant and $T ,$ absolute $e$. temperature)
- A$\frac{7}{2} k _{ B } T$
- B$\frac{1}{2} k _{ B } T$
- ✓$\frac{3}{2} k _{ B } T$
- D$\frac{5}{2} k_{B} T$
✓
Answer
Correct option: C.
$\frac{3}{2} k _{ B } T$
c
Average thermal energy $=\frac{3}{2} K _{ B }\, T$
Average thermal energy $=\frac{3}{2} K _{ B }\, T$
where $3$ is translational degree of freedom For monoatomic gas total degree of freedom
$f =3$ (translational degree of freedom)
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