$\therefore \frac{{{E_2}}}{{{E_1}}} = \frac{{{T_2}}}{{{T_1}}} = \frac{{600}}{{300}} = 2$
$\therefore \,\,{E_2} = 2{E_1}\,\,\,$
$\therefore \,\,\,{E_2} = 2 \times 6.21 \times {10^{ - 21}}\,\, = 12.42 \times {10^{ - 21}}\,J$
${\upsilon _{rms}} \propto \sqrt T $ પરથી $\frac{{{{({\upsilon _{rms}})}_2}}}{{{{({\upsilon _{rms}})}_1}}} = \sqrt {\frac{{{T_2}}}{{{T_1}}}} = \,\sqrt {\frac{{600}}{{300}}} \, = \,\sqrt 2 \,\,$
$\therefore {({\upsilon _{rms}})_2}\, = \,\sqrt 2 {({\upsilon _{rms}})_1}$
$\therefore {({\upsilon _{rms}})_2}\,\, = \,\sqrt 2 \times 325\,\, = \,459.6\,m/s$
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(Given, atmospheric pressure $=10^5 \mathrm{Nm}^{-2}$, density of mercury $=1.36 \times 10^4 \mathrm{~kg} \mathrm{~m}^3, \mathrm{~g}=10 \mathrm{~ms}^2$, $\left.\pi=\frac{22}{7}\right)$