MCQ
The better reducing agent at $7100^{\circ} \mathrm{C}$ is:
- ✓$CO\ ($Ellingham diagram$)$
- BCoke
- CBoth are equal
- DNone of these
✓
Answer
Correct option: A.
$CO\ ($Ellingham diagram$)$
Ellingham diagram is a graph between $\triangle\text{G}^\circ$ and temperature values which determines the spontaneity of a reaction. At $7100^{\circ} \mathrm{C}, \mathrm{CO}$ acts as better reducing agent by seeing the diagram.
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