The blocks are given velocity in the direction shown in figure. Co-efficient of friction between two blocks shown in figure is $μ = 0.5$. Take $g = 10\ m/s^2$
(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct
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$a_{2}=-\frac{20}{4}=-5 \mathrm{m} / \mathrm{s}^{2}$
$a_{1}=\frac{20}{2}=+10 \mathrm{m} / \mathrm{s}^{2}$
Relative motion stopped when
$\mathrm{v}_{1}=\mathrm{v}_{2}$ $-6+10 t=12-5 t$
$t=\frac{18}{15}=1.2 \sec$
common velocity $=-6+10 t$
$=-6+10 \times 1.2=6 \mathrm{m} / \mathrm{s}$
Displacement of $4 \mathrm{kg}$ block
$=\frac{12 \times 6}{5}-\frac{1}{2} \times 5 \times\left(\frac{6}{5}\right)^{2}=\frac{72}{5}-\frac{36}{10}=10.8 \mathrm{m}$
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