MCQ
The bond order in $NO ^{+}$molecule is __________ .
- A4
- B1
- C3
- D2
✓
Answer
C. 3
Explanation:
Electronic configuration of $NO ^{+}$molecule is
$\begin{array}{l}
NO^{+}: K K(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_2\right)^2\left(\pi 2 p_x\right)^2 \\
\equiv\left(\pi 2 p_\nu\right)^2\left(\pi^* 2 p_x\right)^0
\end{array}$
KK represents closed K shell structure $(\sigma 1 s)^2\left(\sigma^* 1 s\right)^2$
Bond order of $NO ^{+}$molecule $=\frac{N_b-N_a}{2}=\frac{8-2}{2}=3$
Explanation:
Electronic configuration of $NO ^{+}$molecule is
$\begin{array}{l}
NO^{+}: K K(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_2\right)^2\left(\pi 2 p_x\right)^2 \\
\equiv\left(\pi 2 p_\nu\right)^2\left(\pi^* 2 p_x\right)^0
\end{array}$
KK represents closed K shell structure $(\sigma 1 s)^2\left(\sigma^* 1 s\right)^2$
Bond order of $NO ^{+}$molecule $=\frac{N_b-N_a}{2}=\frac{8-2}{2}=3$
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