A star initially has $10^{40}$ deuterons. It produces energy via the processes, and ${ }_1 H ^2+$ ${ }_1 H ^3 \rightarrow{ }_1 H ^3+p$. If the average power radiated by the star is $10^{16} W$, the deuteron supply of the star is exhausted in a time of the order of:-
The masses of the nuclei are as follows:
$\begin{array}{l}
M\left(H^2\right)=2.014 amu ; \\
M\left(H^2\right)=1.007 amu ; M(n)=1.008 amu ; M\left(He^4\right)=4.001 amu
\end{array}$
The masses of the nuclei are as follows:
$\begin{array}{l}
M\left(H^2\right)=2.014 amu ; \\
M\left(H^2\right)=1.007 amu ; M(n)=1.008 amu ; M\left(He^4\right)=4.001 amu
\end{array}$
- A$10^{16} s$
- B$10^6 s$
- C$10^8 s$
- D$10^{12} s$
