The bulk modulus of rubber is $9.1 \times 10^8\,N/m^2$. To what depth a rubber ball be taken in a lake so that its volume is decreased by $0.1\%$ ? ....... $m$
Medium
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$\mathrm{K}=\frac{\Delta \mathrm{P}}{\left(-\frac{\Delta \mathrm{V}}{\mathrm{V}}\right)}=\frac{\mathrm{h} \rho \mathrm{g}}{\left(-\frac{\Delta \mathrm{V}}{\mathrm{V}}\right)}$
$9.1 \times 10^{8}=\frac{\mathrm{h} \times 10^{3} \times 10}{\left(\frac{0.1}{100}\right)} \quad \Rightarrow \mathrm{h}=91 \mathrm{m}$
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