A copper wire and a steel wire of the same diameter and length are connected end to end and a force is applied, which stretches their combined length by $1\, cm$. The two wires will have
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(d) ${\rm{Stress}} = \frac{{{\rm{Force}}}}{{{\rm{area}}}}$.
In the present case, force applied and area of cross-section of wires are same, therefore stress has to be the same.
${\rm{Strain}} = \frac{{{\rm{Stress}}}}{Y}$
Since the Young’s modulus of steel wire is greater than the copper wire, therefore, strain in case of steel wire is less than that in case of copper wire.
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