MCQ
The calculation for mode for the following distribution is given below:
Here, the maximum frequency is 32 and the corresponding modal class is $30-40$.
$\therefore \quad l=30, h=10, f_0=12, f_1=32, f_2=20($ Step 1$)$
$\therefore \quad$ Mode $=l+\left(\frac{f_1-f_0}{2 f_1-f_0-f_2}\right) \times h \quad$ (Step 2)
$=30+\left(\frac{32-12}{64-12-20}\right) \times 10=30+\frac{25}{4}=36.25$ (Step 3$)$
In which step is there an error in solving?
Here, the maximum frequency is 32 and the corresponding modal class is $30-40$.
$\therefore \quad l=30, h=10, f_0=12, f_1=32, f_2=20($ Step 1$)$
$\therefore \quad$ Mode $=l+\left(\frac{f_1-f_0}{2 f_1-f_0-f_2}\right) \times h \quad$ (Step 2)
$=30+\left(\frac{32-12}{64-12-20}\right) \times 10=30+\frac{25}{4}=36.25$ (Step 3$)$
In which step is there an error in solving?
| Marks | Number of students |
| 0-10 | 6 |
| 10-20 | 10 |
| 20-30 | 12 |
| 30-40 | 32 |
| 40-50 | 20 |
- AStep 1
- BStep 2
- CStep 3
- ✓There is no error
