The capacity and the energy stored in a parallel plate condenser with air between its plates are respectively ${C_o}$ and ${W_o}$. If the air is replaced by glass (dielectric constant $= 5$ ) between the plates, the capacity of the plates and the energy stored in it will respectively be
  • A$5{C_o},\;5{W_o}$
  • B$5{C_o},\;\frac{{{W_0}}}{5}$
  • C$\frac{{{C_o}}}{5},\;5{W_o}$
  • D$\frac{{{C_o}}}{5},\frac{{{W_o}}}{5}$
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The area of the plates of a parallel plate capacitor is $A$ and the gap between them is $d$. The gap is filled with a non-homogeneous dielectric whose dielectric constant varies with the distance $‘y’$ from one plate as : $K = \lambda \ sec(\pi y/2d)$, where $\lambda $ is a dimensionless constant. The capacitance of this capacitor is
    View Solution
  • 2
    A series combination of $n_1$ capacitors, each of value $C_1$ is charged by a source of potential difference $4\, V.$ When another parallel combination of $n_2$ capacitors, each of value $C_2,$ is charged by a source of potential difference $V$, it has the same (total) energy stored in it, as the first combination has. The value of $C_2,$ in terms of $C_1$ is then
    View Solution
  • 3
    The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (5{x^2} + 10x - 9)\,volt$. Value of electric field at $x = 1$ is......$V/m$
    View Solution
  • 4
    The capacitance of an air capacitor is $15\,\mu F$ the separation between the parallel plates is $6\,mm$. A copper plate of $3\,mm$ thickness is introduced symmetrically between the plates. The capacitance now becomes.........$\mu F$
    View Solution
  • 5
    A parallel plate capacitor having a separation between the plates $d$ , plate area $A$ and material with dielectric constant $K$ has capacitance $C_0$. Now one-third of the material is replaced by another material with dielectric constant $2K$, so that effectively there are two capacitors one with area $\frac{1}{3}\,A$ , dielectric constant $2K$ and another with area $\frac{2}{3}\,A$ and dielectric constant $K$. If the capacitance of this new capacitor is $C$ then $\frac{C}{{{C_0}}}$ is
    View Solution
  • 6
    If capacitor connected across $AB$ is charged to $Q$ and then switch is shifted to $2$ . The heat released after that
    View Solution
  • 7
    A charged capacitor is allowed to discharge through a resistance $2\,\Omega $ by closing the switch $S $ at the instant $t = 0$. At time $t = ln$ $2$ $\mu s$, the reading of the ammeter falls half of its initial value. The resistance of the ammeter equal to
    View Solution
  • 8
    The combination of capacitors with ${C_1} = 3\,\mu \,F,\,{C_2} = 4\,\mu \,F$ and ${C_3} = 2\,\mu \,F$ is charged by connecting $AB$ to a battery. Consider the following statements

    $I.$ Energy stored in ${C_1}$ $=$ Energy stored in ${C_2}$ $+$ Energy stored in ${C_3}$

    $II.$ Charge on ${C_1}$ $=$ Charge on ${C_2}$ $+$ Charge on ${C_3}$

    $III.$ Potential drop across ${C_1}$ $=$ Potential drop across ${C_2}$ $=$ Potential drop across ${C_3}$

    Which of these is/are correct

    View Solution
  • 9
    The electric field intensity produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is $E$. The electric field intensity produced by the radiation coming from $60\, W$ at the same distance is $\sqrt{\frac{x}{5}} E$. Where the value of $x=......... .$
    View Solution
  • 10
    Two electrons are moving towards each other, each with a velocity of $10^6 \,m / s$. What will be closest distance of approach between them is ......... $m$
    View Solution