The capacity of a parallel plate condenser is $10\,\mu \,F$, when the distance between its plates is $8 \,cm$. If the distance between the plates is reduced to $4\, cm$, then the capacity of this parallel plate condenser will be.........$\mu \,F$
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$C \propto \frac{1}{d} \Rightarrow \frac{{{C_1}}}{{{C_2}}} = \frac{{{d_2}}}{{{d_1}}}$ so $\frac{{{C_2}}}{{10}} = \frac{8}{4} \Rightarrow {C_2} = 20\,\mu F$
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