A capacitor of capacitance $\mathrm{C}$ and potential $\mathrm{V}$ has energy $E$. It is connected to another capacitor of capacitance $2 \mathrm{C}$ and potential $2 \mathrm{~V}$. Then the loss of energy is $\frac{x}{3} E$, where $\mathrm{x}$ is____________.
JEE MAIN 2024, Diffcult
Download our app for free and get started
Energy loss $=\frac{1}{2} \frac{C_1 C_2}{C_1+C_2}\left(V_1-V_2\right)^2$
$ =\frac{2}{3} \cdot E $
$ \therefore x=2$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Five capacitors together with their capacitances are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\, volt.$ The equivalent capacitance between the point $A$ and $B$ and charge on capacitor $5\,\mu F$ will be respectively :-
The diagram shows three infinitely long uniform line charges placed on the $X, Y $ and $Z$ axis. The work done in moving a unit positive charge from $(1, 1, 1) $ to $(0, 1, 1) $ is equal to
Three capacitors each of capacitance $1\,\mu F$ are connected in parallel. To this combination, a fourth capacitor of capacitance $1\,\mu F$ is connected in series. The resultant capacitance of the system is.......$\mu F$
Two charges of magnitude $5\, nC$ and $-2\, nC$, one placed at points $(2\, cm, 0, 0)$ and $(x\, cm, 0, 0)$ in a region of space, where there is no other external field. If the electrostatic potential energy of the system is $ - 0.5\,\mu J$. The value of $x$ is.....$cm$
An electric dipole moment $\vec p = (2.0\hat i + 3.0\hat j)$ $\mu C. $ $m$ is placed in a uniform electric field $\vec E = (3.0\hat i + 2.0\hat k)$ $×$$10^5$ $N$ $C^{-1}$.
A paralle plate capacitor is made up of stair like structure with a palte area $A$ of each stair and that is connected with a wire of length $b$, as shown in the figure. The capacitance of the arrangement is $\frac{ x }{15} \frac{\varepsilon_{0} A }{ b }$. The value of $x$ is ............
A capacitor having capacitance $C$ is charged to a voltage $V$. It is then removed and connected in parallel with another identical capacitor which is uncharged. The new charge on each capacitor is now