The capacity of an air condenser is $2.0\, \,\mu F$. If a medium is placed between its plates. The capacity becomes $ 12\, \,\mu F$. The dielectric constant of the medium will be
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(d) Dielectric constant of medium
$K = \frac{{{\rm{Capacity \,of \,condenser \,with \,medium}}}}{{{\rm{Capacity\, of \,condenser}}}} = \frac{{12}}{{2.0}} = 6$
$K = \frac{{{\rm{Capacity \,of \,condenser \,with \,medium}}}}{{{\rm{Capacity\, of \,condenser}}}} = \frac{{12}}{{2.0}} = 6$
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