The two plates $X $ and $Y$ of a parallel plate capacitor of capacitance $C$ are given a charge of amount $Q$ each. $X$ is now joined to the positive terminal and $Y$ to the negative terminal of a cell of $emf$ $E = Q/C$.
  • ACharge of amount $Q$ will flow from the negative terminal to the positive terminal of the cell inside it.
  • BThe total charge on the plate $X$ will be $2Q$.
  • CThe total charge on the plate $Y$ will be zero.
  • D
    all of the above
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