The coefficient of static friction, ${\mu _s},$ between block $A$ of mass $2\, kg$ and the table as shown in the figure is $0.2$. ........ $kg$ would be the maximum mass value of block $B$ so that the two blocks do not move. The string and the pulley are assumed to be smooth and massless. $(g = 10\,m/{s^2})$
AIPMT 2004, Medium
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(d) ${\mu _s} = \frac{{{m_B}}}{{{m_A}}}$ $⇒$ $0.2 = \frac{{{m_B}}}{2}$ $⇒$ ${m_B} = 0.4\;kg$
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