(The coefficient of viscosity of water is $9.8 \times 10^{-6}$ $\left.\mathrm{N} \mathrm{s} / \mathrm{m}^2\right)$
($P_0$ = atmospheric pressure)
Statement $I$ : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation $\mathrm{P}_1-\mathrm{P}_2=\rho \mathrm{g}\left(\mathrm{h}_2-\mathrm{h}_1\right)$
Statement $II$ : In ventury tube shown $2 \mathrm{gh}=v_1^2-v_2^2$
In the light of the above statements, choose the most appropriate answer from the options given below.


| Column - $\mathrm{I}$ | Column - $\mathrm{II}$ |
| $(a)$ Viscous force | $(i)$ $\left[ {{M^1}{L^1}{T^{ - 2}}} \right]$ |
| $(b)$ Coefficient of viscosity | $(ii)$ $\left[ {{M^1}{L^{ - 1}}{T^{ - 1}}} \right]$ |
| $(iii)$ $\left[ {{M^1}{L^{ - 1}}{T^{ - 2}}} \right]$ |