MCQ
The compounds that will give an isomer of  $2; 2-$ dimethyl propane on catalytic hydrogenation are

$(1)$ $\begin{array}{*{20}{c}}
  {C{H_3}CH = C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(2)$ $C{H_3}CH = CHC{H_3}$

$(3)$ $\mathop {C{H_3}C}\limits^{\begin{subarray}{l} 
  \,\,\,\,\,\,\,\,{\begin{array}{*{20}{c}}
  {}&H 
\end{array}} \\ 
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,| 
\end{subarray} }  = CHC{H_2}C{H_3}$

$(4)$ $\begin{array}{*{20}{c}}
  {C{H_3}C = C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_{3\,\,}}\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

  • A
    $1$ and $4$
  • B
    $2$ and $4$
  • $1$ and $3$
  • D
    $1$ and $2$

Answer

Correct option: C.
$1$ and $3$
c
Compounds that give an two isomer of $2$-dimethyl propane on catalystic hydrogenation are as follows:-

$\begin{array}{*{20}{c}}
  {C{H_3}CH = C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

and

$\mathop {C{H_3}C}\limits^{\begin{subarray}{l} 
  \,\,\,\,\,\,\,\,{\begin{array}{*{20}{c}}
  {}&H 
\end{array}} \\ 
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,| 
\end{subarray} }  = CHC{H_2}C{H_3}$

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