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STD 12 - 14. Semicondutor electronics — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 14. Semicondutor electronics4 Marks
MCQ
The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :
  • A
    $\beta=\frac{\alpha}{1+\alpha}$
  • B
    $\alpha=\frac{\beta}{1-\alpha}$
  • C
    $\beta=\frac{1}{1-\alpha}$
  • ✓
    $\alpha=\frac{\beta}{1+\beta}$
✓

Answer

Correct option: D.
$\alpha=\frac{\beta}{1+\beta}$
d
$\alpha=\frac{I_{C}}{I_{E}}, \beta=\frac{I_{C}}{I_{B}}$

$I_{E}=I_{B}+I_{C}$

$\alpha=\frac{I_{C}}{I_{B}+I_{C}}=\frac{1}{\frac{I_{B}}{I_{C}}+1}$

$\alpha=\frac{1}{\frac{1}{\beta}+1}$

$\alpha=\frac{\beta}{1+\beta}$

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