Two wires of copper having the length in the ratio $4 : 1$ and their radii ratio as $1 : 4$ are stretched by the same force. The ratio of longitudinal strain in the two will be
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(b) ${\rm{strain}} \propto {\rm{stress}} \propto \frac{{\rm{F}}}{{\rm{A}}}$
Ratio of strain =$\frac{{{A_2}}}{{{A_1}}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} = {\left( {\frac{4}{1}} \right)^2} = \frac{{16}}{1}$
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