MCQ
The correct statement among the following is
  • A
    $\left( SiH _3\right)_3 N$ is planar and less basic than $\left( CH _3\right)_3 N$
  • B
    $\left( SiH _3\right)_3 N$ is pyramidal and less basic than $\left( CH _3\right)_3 N$
  • C
    $\left( SiH _3\right)_3 N$ is pyramidal and more basic than $\left( CH _3\right)_3 N$
  • D
    $\left( SiH _3\right)_3 N$ is planar and more basic than $\left( CH _3\right)_3 N$

Answer

A. $\left( SiH _3\right)_3 N$ is planar and less basic than $\left( CH _3\right)_3 N$
Explanation:
The correct statement is that $\left( SiH _3\right)_3 N$ is planar and less basic than $\left( CH _3\right)_3 N$. The compounds trimethylamine $\left( CH _3\right)_3 N$ and triethylamine $\left( SiH _3\right)_3 N$ have similar formulae but have totally different structures. In trimethylamine the arrangement of electrons is as follows:
Image
In trisilylamine, three $sp ^2$ orbitals are used for a-bonding, giving a plane triangular structure.
Image

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