The current density in a cylindrical wire of radius $4 \; mm$ is $4 \times 10^{6} \; Am ^{-2}$. The current through the outer portion of the wire between radial distance $\frac{R}{2}$ and $R$ is $\dots \; \pi A .$
  • A$-48$
  • B$48$
  • C$-58$
  • D$58$
JEE MAIN 2022, Medium
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