The current in the windings on a toroid is $2.0\,A$. There are $400$ $turns$ and the mean circumferential length is $40\,cm$. If the inside magnetic field is $1.0\,T$, the relative permeability is near to
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(d) $B = \frac{{{\mu _0}{\mu _r}Ni}}{{2\pi r}} \Rightarrow 1 = \frac{{4\pi \times {{10}^{ - 7}} \times {\mu _r} \times 400 \times 2}}{{0.4}} \Rightarrow {\mu _r} = 400$
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