The decreasing order of boiling points of the following alcohols is?
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$3-$methylbutan$-2-ol$ is a secondary alcohol $\ce{CH_3CH(CH_3)CH(OH)CH_{3}}$
$2-$methylbutan$-2-ol$ is a tertiary alcohol
$\ce{CH_{3}CH_2C(CH_3)(OH)CH_{3}}$
pentan$-1-ol$ is a primary alcohol
$\ce{CH_{3}CH_{2}CH_2CH_2CH_2OH}$
Boiling point of alcohols is determined by the ease and extent of $H-$bonding among the alcohol molecules. Tertiary alcohols being highly hindered will have least hydrogen bonding and thus low boiling point as compared to less hindered secondary alcohol.
Therefore the order of boiling point is primary alcohol $>$ secondary alcohol>tertiary alcohol as:
pentan$-1-ol > 3-$methylbutan$-2-ol > 2-$methylbutan$-2-ol.$
$2-$methylbutan$-2-ol$ is a tertiary alcohol
$\ce{CH_{3}CH_2C(CH_3)(OH)CH_{3}}$
pentan$-1-ol$ is a primary alcohol
$\ce{CH_{3}CH_{2}CH_2CH_2CH_2OH}$
Boiling point of alcohols is determined by the ease and extent of $H-$bonding among the alcohol molecules. Tertiary alcohols being highly hindered will have least hydrogen bonding and thus low boiling point as compared to less hindered secondary alcohol.
Therefore the order of boiling point is primary alcohol $>$ secondary alcohol>tertiary alcohol as:
pentan$-1-ol > 3-$methylbutan$-2-ol > 2-$methylbutan$-2-ol.$
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