MCQ
The decreasing order of the second ionization potential of $\ce{K, Ca}$ and $\ce{Ba}$ is:
- ✓$\ce{K > Ca > Ba}$
- B$\ce{Ca > Ba > K}$
- C$\ce{Ba > K > Ca}$
- D$\ce{K > Ba > Ca}$
✓
Answer
Correct option: A.
$\ce{K > Ca > Ba}$
As we move down the group size increases and the electrons experience less effective nuclear charge. Due to this reason, ionization potential decreases down the group. Thus, the second ionization potential of $\ce{Ca}$ is greater than that of $\ce{Ba}.$
The second ionization potential of $\ce{K}$ is greater than that of $\ce{Ca}$ as $\ce{K}$ acquires stable noble gas configuration after losing one electron.
The second ionization potential of $\ce{K}$ is greater than that of $\ce{Ca}$ as $\ce{K}$ acquires stable noble gas configuration after losing one electron.
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