$2Al{(s)}+6HCl{(aq)} \rightarrow 2Al^{^{3+}}{(aq)}+6Cl^-{(aq)} +3H_2{(g)}$
$\therefore \;1 \;mole$ of $\mathrm{HCl}(\mathrm{aq})$ produces $=\frac{3}{6}$ moles of $\mathrm{H}_{2}(\mathrm{g})=\frac{1}{2}\; moles$ of $\mathrm{H}_{2}(\mathrm{g})$
From avogadro hypothesis we know at $STP \;1\; mole$ of any as occupies $22.4 \mathrm{\,L}$
$\therefore \frac{1}{2}$ moles of $\mathrm{H}_{2}(\mathrm{g})$ occupies $=\frac{1}{2} \times 22.4=11.2 \mathrm{\,L}$
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$(i) $ in filling a group of orbitals of equal energy, it is energetically preferable to assign electrons to empty orbitals rather than pair them into a particular orbital.
$(ii)$ When two electrons are placed in two different orbitals, energy is lower if the spins are parallel.are valid for
