The deflection in moving coil galvanometer falls from $25$ divisions to $5$ division when a shunt of $24\ \Omega$ is applied. The resistance of galvanometer coil will be :
JEE MAIN 2024, Diffcult
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Let $\mathrm{x}=$ current/division
Now $5 \mathrm{x} \times \mathrm{G}=20 \mathrm{x} \times 24$
$ \mathrm{G}=4 \times 24 $
$ \mathrm{G}=96 \ \Omega$
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