The circuit shown in the figure consists of a charged capacitor of capacity $3\, \mu F$ and a charge of $30\, \mu C$. At time $t =0,$ when the key is closed, the value of current flowing through the $5\, M \Omega$ resistor is $'x'$ $\mu-A$. The value of $'x'$ to the nearest integer is .........
JEE MAIN 2021, Medium
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$i _{0}=\frac{ V }{ R }=\frac{30 / 3}{5 \times 10^{6}}=2 \times 10^{-6}$
$\therefore$ Ans. $=2.00$
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