MCQ
The dimensional formula for Planck's constant $(h)$ is
- A$M{L^{ - 2}}{T^{ - 3}}$
- B$M{L^2}{T^{ - 2}}$
- ✓$M{L^2}{T^{ - 1}}$
- D$M{L^{ - 2}}{T^{ - 2}}$
✓
Answer
Correct option: C.
$M{L^2}{T^{ - 1}}$
c
(c) $E = hv \Rightarrow [M{L^2}{T^{ - 2}}] $$= [h]\,[{T^{ - 1}}] $$\Rightarrow [h] = [M{L^2}{T^{ - 1}}]$
(c) $E = hv \Rightarrow [M{L^2}{T^{ - 2}}] $$= [h]\,[{T^{ - 1}}] $$\Rightarrow [h] = [M{L^2}{T^{ - 1}}]$
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