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1. units,dimensions and measurement — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics1. units,dimensions and measurement1 Mark
MCQ
The dimensions of $\frac{\alpha}{\beta}$ in the equation $F=\frac{\alpha-t^2}{\beta v^2}$, where $F$ is the force, $v$ is velocity and $t$ is time, is ..........
  • A
    $\left[ MLT ^{-1}\right]$
  • B
    $\left[ ML ^{-1} T ^{-2}\right]$
  • ✓
    $\left[M L^3 T^{-4}\right]$
  • D
    $\left[ ML ^2 T ^{-4}\right]$
✓

Answer

Correct option: C.
$\left[M L^3 T^{-4}\right]$
c
(c)

$F=\frac{\alpha-t^2}{\beta v^2}$

Dimensionally, $\alpha=\left[ T ^2\right]$

$\left[M L T^{-2}\right]=\frac{\left[ T ^2\right]}{\beta\left[L^2 T^{-2}\right]}$

$\beta=\frac{ T ^2}{\left[ MLT ^{-2} \cdot L ^2 T ^{-2}\right]}$

$\Rightarrow \beta=\left[ M ^{-1} L ^{-3} T ^6\right]$

Dimensions of $\frac{\alpha}{\beta}=\frac{ T ^2}{ M ^{-1} L ^{-3} T ^6}=\left[ ML ^3 T ^{-4}\right]$

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