MCQ
A soap bubble is blown to a diameter of $7 \mathrm{~cm}$. $36960 \mathrm{erg}$ of work is done in blowing it further. If surface tension of soap solution is $40 \mathrm{dyne} / \mathrm{cm}$ then the new radius is______. $\mathrm{cm}$. Take $:\left(\pi=\frac{22}{7}\right)$.
  • A
    $5$
  • $7$
  • C
    $10$
  • D
    $15$

Answer

Correct option: B.
$7$
b
$\omega=\Delta \mathrm{U}=\mathrm{S} \Delta \mathrm{A}$

$36960$ $\mathrm{erg}=\frac{40 \text { dyne }}{\mathrm{cm}} 8 \pi\left[(\mathrm{r})^2-\left(\frac{7}{2}\right)^2\right] \mathrm{cm}^2$

$\mathrm{r}=7 \mathrm{~cm}$

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