The dimensions of four wires of the same material are given below. In which wire the increase in length will be maximum when the same tension is applied
Medium
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(d)$Y = \frac{F}{A}\;\frac{L}{A} \Rightarrow l \propto \frac{L}{A} \propto \frac{L}{{\pi {d^2}}}$
$l \propto \frac{L}{{{d^2}}}$ [As F and Y are constant]
The ratio of $\frac{L}{{{d^2}}}$is maximum for case $(d)$
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