MCQ
The dimensions of $\left(\frac{ B ^{2}}{\mu_{0}}\right)$ will be.

(if $\mu_{0}$ : permeability of free space and $B$ : magnetic field)

  • A
    $\left[ ML ^{2} T ^{-2}\right]$
  • B
    $\left[ ML T ^{-2}\right]$
  • $\left[ ML ^{-1} T ^{-2}\right]$
  • D
    $\left[ ML ^{2} T ^{-2} A ^{-1}\right]$

Answer

Correct option: C.
$\left[ ML ^{-1} T ^{-2}\right]$
c
$u =\frac{ B ^{2}}{2 \mu_{0}}$

$u \rightarrow$ Energy per unit volume

$\left[\frac{ B ^{2}}{\mu_{0}}\right]=[ u ]=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ L ^{3}\right]}=\left[ ML ^{-1} T ^{-2}\right]$

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