MCQ
The dimensions of universal gravitational constant are
- A${M^{ - 2}}{L^2}{T^{ - 2}}$
- ✓${M^{ - 1}}{L^3}{T^{ - 2}}$
- C$M{L^{ - 1}}{T^{ - 2}}$
- D$M{L^2}{T^{ - 2}}$
✓
Answer
Correct option: B.
${M^{ - 1}}{L^3}{T^{ - 2}}$
b
(b) $F = \frac{{G{m_1}{m_2}}}{{{d^2}}} \Rightarrow G = \frac{{F{d^2}}}{{{m_1}{m_2}}}$
(b) $F = \frac{{G{m_1}{m_2}}}{{{d^2}}} \Rightarrow G = \frac{{F{d^2}}}{{{m_1}{m_2}}}$
$[G] = \frac{{[ML{T^{ - 2}}][{L^2}]}}{{[{M^2}]}} = [{M^{ - 1}}{L^3}{T^{ - 2}}]$
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