MCQ
The displacement time equation of a particle executing $SHM$ is : $x = A \,sin\,(\omega t + \phi )$. At time $t = 0$ position of the particle is $x = A/2$ and it is moving along negative $x-$ direction. Then the angle $\phi $ can be
  • A
    $\pi /6$
  • B
    $\pi /3$
  • C
    $2\pi /3$
  • $5\pi /6$

Answer

Correct option: D.
$5\pi /6$
d
$\phi=150^{\circ}$

$\mathrm{x}=\mathrm{A} \sin (\omega \mathrm{t}+5 \pi / 6)$

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