MCQ
The displacement time equation of a particle executing $SHM$ is : $x = A \,sin\,(\omega t + \phi )$. At time $t = 0$ position of the particle is $x = A/2$ and it is moving along negative $x-$ direction. Then the angle $\phi $ can be
- A$\pi /6$
- B$\pi /3$
- C$2\pi /3$
- ✓$5\pi /6$

