MCQ
The displacement-time graph for two particles $A$ and $B$ is as follows. The ratio $\frac{v_A}{v_B}$ is
- A$1: 2$
- B$1: \sqrt{3}$
- C$\sqrt{3}: 1$
- ✓$1: 3$
✓
Answer
Correct option: D.
$1: 3$
d
(d)
(d)
The slope of line $A$ is $\tan 30^{\circ}$ and $B=\tan 60^{\circ}$
$\frac{v_A}{v_B}=\frac{\tan 30^{\circ}}{\tan 60^{\circ}}=\frac{\frac{1}{\sqrt{3}}}{\sqrt{3}}=\frac{1}{3} \Rightarrow v_A: v_B=1: 3$
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