MCQ
The distance between (6, 5) and (-3, 4) is:
- A$\sqrt{82}$
- B$\sqrt{83}$
- C$\sqrt{84}$
- DNone
The distance between (6, 5) and (-3, 4) is:
Solution:
The given points are (6, 5) and (-3, 4)
The distance is given as $=\sqrt {(\text{x}_2-\text{x}_1)^2+(\text{y}_2-\text{y}_1)^2}$
$=\sqrt {(6+3)^2+(4-5)^2}$
$=\sqrt {9^2+1^2}$
$=\sqrt {81+1}=\sqrt {82}$
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