The distance between the circular plates of a parallel plate condenser $40\,mm$ in diameter, in order to have same capacity as a sphere of radius $1\;metre$ is....$mm$
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(b) $4\pi {\varepsilon _0}r = \frac{{{\varepsilon _0}A}}{d}$ $==>$ $d = \frac{A}{{4\pi r}} = \frac{{\pi {{(20 \times {{10}^{ - 3}})}^2}}}{{4\pi \times 1}} = 0.1\,mm$
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