MCQ
The distance between the points $A (7,13)$ and $B(10,9)$ are
- ✓$5$ units
- B$6$ units
- C$7$ units
- D$8$ units
✓
Answer
Correct option: A.
$5$ units
The given points are $A (7,13)$ and $B (10,9)$.
Then, $x _1=7, y _1=13$ and $x _2=10, y _2=9$
$\therefore AB=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$=\sqrt{(10-7)^2+(9-13)^2}$
$=\sqrt{(3)^2+(-4)^2}$
$=\sqrt{9+16}$
$=\sqrt{25}$
$=5 \text { units. }$
Then, $x _1=7, y _1=13$ and $x _2=10, y _2=9$
$\therefore AB=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$=\sqrt{(10-7)^2+(9-13)^2}$
$=\sqrt{(3)^2+(-4)^2}$
$=\sqrt{9+16}$
$=\sqrt{25}$
$=5 \text { units. }$
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