MCQ
The distance $CP$ is the:


- ACenter of curvature
- ✓Radius of curvature
- CFocal length
- DNone of these

The distance $CP$ is the radius of curvature.

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$ { }_3 \mathrm{Li}^6+{ }_0 \mathrm{n}^1 \rightarrow{ }_2 \mathrm{He}^4+{ }_1 \mathrm{H}^3 $
$ { }_1 \mathrm{H}^2+{ }_1 \mathrm{H}^3 \rightarrow{ }_2 \mathrm{He}^4+{ }_0 \mathrm{n}^1$
During the explosion the energy released is approximately
[Given : $\mathrm{M}(\mathrm{Li})=6.01690\ \mathrm{amu} . \mathrm{M}\left({ }_1 \mathrm{H}^2\right)=2.01471 \ amu.$ $\mathrm{M}\left({ }_2 \mathrm{He}^4\right)=4.00388\ \mathrm{amu}$,$ and\ $$1 \ \mathrm{amu}=931.5$ $\mathrm{MeV}]$
