The eccentricity of the conic 9x^2+25y^2=225 is: - Vidyadip

MCQ

The eccentricity of the conic $9\text{x}^2+25\text{y}^2=225$ is:

A
$\frac{2}{5}$
✓
$\frac{4}{5}$
C
$\frac{1}{3}$
D
$\frac{1}{5}$

✓

Answer

Correct option: B.

$\frac{4}{5}$

$9\text{x}^2+25\text{y}^2=225$
$\Rightarrow\frac{\text{x}^2}{25}+\frac{\text{y}^2}{9}=1$
Comparing it with $\Rightarrow\frac{\text{x}^2}{\text{a}^2}+\frac{\text{y}^2}{\text{b}^2}=1,$ we get:
$\text{a}=5$ and $\text{b}=3$
Here, a > b, so the major and the minor axes of the ellipse are along the x−axis and y−axis, respectively.
Now, $\text{e}=\sqrt{1-\frac{\text{b}^2}{\text{a}^2}}$
$\Rightarrow\text{e}=\sqrt{1-\frac{9}{25}}$
$\Rightarrow\text{e}=\sqrt{\frac{16}{25}}$
$\Rightarrow\text{e}=\frac{4}{5}$

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